$$\frac{{11}}{5}$$ of a number A is 22% of a number B. The number B is equal to 2.5% of a third number C. If the value of C is 5500, then the sum of 80% of A and 40% of B is:

Solution(By Examveda Team)

$$\eqalign{ & \frac{{11}}{5}A = \frac{{22}}{{100}}B \cr & \frac{A}{B} = \frac{1}{{10}} \cr & B = \frac{{25}}{{1000}}C \cr & \frac{B}{C} = \frac{1}{{40}} \cr} $$
\[\begin{array}{*{20}{c}} {A\,\,\,:\,\,\,B\,\,\,:\,\,\,C} \\ {\,1\,\,\,\,\,\,\,\,\,\,10\,\,\,\,\,\,\,\,\,\,10} \\ {\,1\,\,\,\,\,\,\,\,\,\,\,\,1\,\,\,\,\,\,\,\,\,\,\,40} \\ {\overline {\,\,1\,\,:\,\,40\,\,:\,\,400\,} } \end{array}\]
$$\eqalign{ & 400 \to 5500 \cr & 400 \to \frac{{55}}{4} \cr & A \to \frac{{55}}{4} \cr & B \to \frac{{550}}{4} \cr & {\text{According to the question,}} \cr & \left( {\frac{{80}}{{100}} \times \frac{{55}}{4}} \right) + \left( {\frac{{40}}{{100}} \times \frac{{550}}{4}} \right) \cr & = 11 + 55 \cr & = 66 \cr} $$