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A 300 metre long train crosses a platform in 39 seconds while it crosses a signal pole in 18 seconds. What is the length of the platform?

Answer & Solution
Correct Answer: Option B
$$\eqalign{ & {\text{Speed}} = {\frac{{300}}{{18}}} \,{\text{m/sec}} \cr & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = \frac{{50}}{3}\,{\text{m/sec}} \cr & {\text{Let}}\,{\text{the}}\,{\text{length}}\,{\text{of}}\,{\text{the}}\,{\text{platform}}\,{\text{be}}\,x\,{\text{metres}}{\text{.}} \cr & {\text{Then}}, {\frac{{x + 300}}{{39}}} = \frac{{50}}{3} \cr & \Rightarrow 3\left( {x + 300} \right) = 1950 \cr & \Rightarrow x = 350\,m. \cr} $$
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2 Comments
Prashanth Bilimagga
Prashanth Bilimagga 5 years ago
Speed of train = 300/18= 50/3 m/s
Time taken by train to cover platform= 39-18=21s
Platform length = speed * time
= 50/3 * 21= 350m
Prashant Suryawanshi
Prashant Suryawanshi 7 years ago
300/18=16.66
that mean in 18sec train cover only 16.66 m distance
and remaining time is 39-18=21
Therefore 21x16.66=350 m
So the platfom is 350m