A alone can do a work in 14 days. B alone can do the same work in 28 days. C alone can do the same work in 56 days. They start the work together and completed the work such that B was not working on last 2 days and A did not work in last 3 days. In how many days (total) was the work completed?

A. $$\frac{{72}}{7}$$

B. $$\frac{{79}}{7}$$

C. $$\frac{{65}}{7}$$

D. $$\frac{{82}}{7}$$

Answer: Option A

Solution (By Examveda Team)

Work done not done by B = 2 × 2 = 4
Work done not done by A = 3 × 4 = 12
Total work = 56 + 4 + 12 = 72
∴ Total time $$ = \frac{{72}}{{4 + 2 + 1}} = \frac{{72}}{7}{\text{days}}$$