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A and B can do a work in $$26\frac{2}{3}$$ days. B and C together can complete the same work in 48 days, while A and C together can complete the same work in 30 days. How long (in days) will A alone take to complete 60% of the work?
Answer & Solution
Correct Answer:
Option
A
$${\text{A}} = 26\frac{2}{3} = \frac{{80}}{3}$$
2(A + B + C) = 9 + 5 + 8 = 22
(A + B + C) = 11
A = 11 - 5 = 6
60% of total work $$ = \frac{{60}}{{100}} \times 240 = 144$$
$${\text{A}} = \frac{{144}}{6} = 24{\text{ days}}$$
2(A + B + C) = 9 + 5 + 8 = 22
(A + B + C) = 11
A = 11 - 5 = 6
60% of total work $$ = \frac{{60}}{{100}} \times 240 = 144$$
$${\text{A}} = \frac{{144}}{6} = 24{\text{ days}}$$
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