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A and B can do a work together in 18 days. A is three time as efficient as B. In how many days can B alone complete the work?
Answer & Solution
Correct Answer:
Option
B
A : B = 3 : 1
Total work = 4 × 18 = 72 unit
B = \[\frac{{72}}{1}\] = 72 days
Total work = 4 × 18 = 72 unit
B = \[\frac{{72}}{1}\] = 72 days
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