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A, B and C can all together do a piece of work in 10 days, in which B takes 3 times as long as A and C together to do the work. In how many days can B alone do the work?
Answer & Solution
Correct Answer:
Option
B
\[\begin{array}{*{20}{c}}
{}&{\left( {A + C} \right)}&:&B \\
{{\text{Time}}}&1&{}&3 \\
{{\text{Efficiency}}}&3&{}&1
\end{array}\]
$$B\,{\text{alone}} = \frac{{10 \times 4}}{1} = 40\,{\text{days}}$$
$$B\,{\text{alone}} = \frac{{10 \times 4}}{1} = 40\,{\text{days}}$$
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