A binary symmetric channel (BSC) has a transition probability of $$\frac{1}{8}.$$ If the binary transmit symbol X is such that $${{\text{P}}_{\left( {{\text{X}} = {\text{0}}} \right)}} = \frac{9}{{10}},$$ then the probability of error for an optimum receiver will be
A. $$\frac{7}{{80}}$$
B. $$\frac{{63}}{{80}}$$
C. $$\frac{9}{{10}}$$
D. $$\frac{1}{{10}}$$
Answer: Option D
This Question Belongs to Electronics And Communications Engineering >> Information Theory And Coding
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