A binary symmetric channel (BSC) has a transition probability of $$\frac{1}{8}.$$ If the binary transmit symbol X is such that $${{\text{P}}_{\left( {{\text{X}} = {\text{0}}} \right)}} = \frac{9}{{10}},$$   then the probability of error for an optimum receiver will be

A. The same as FDM B. The same as TDM C. A combination of FDM and TDM D. Quite different from FDM and TDM

A. C₂ ≈ 2C₁ B. C₂ ≈ C₁ + B C. C₂ ≈ C₁ + 2B D. C₂ ≈ C₁ + 0.3B

A. 1 and 2 B. 2 and 3 C. 1 and 3 D. None of the above

A. Maximum Likelihood Decoding B. Sequential Decoding C. Both A and B D. None of the above