A binary symmetric channel (BSC) has a transition probability of $$\frac{1}{8}.$$ If the binary transmit symbol X is such that $$P\left( {X = 0} \right) = \frac{9}{{10}},$$ then the probability of error for an optimum receiver will be
A. $$\frac{7}{{80}}$$
B. $$\frac{{63}}{{80}}$$
C. $$\frac{9}{{10}}$$
D. $$\frac{1}{{10}}$$
Answer: Option A

Join The Discussion