A can do a piece of work in 12 days. When he had worked for 3 days. B joined him. If they complete the work in 3 more days, in how many days can B alone finish the work ?
A. 6 days
B. 12 days
C. 4 days
D. 8 days
Answer: Option A
Solution(By Examveda Team)
Total work = 12Efficiency 1 units/day = 12 days time (A)
After 3 days A finishes 3 units.
∴ Work left =12 - 3 = 9 units
9 units of work, 3 units/day = 3 days (A + B)
(A + B)'s one day work = 3 units
A's one day work = 1 unit
B's one day work = 3 - 1 = 2 units
∴ B completes whole work in
$$\eqalign{ & = \frac{{{\text{Total work}}}}{{{\text{Efficiency}}}} \cr & = \frac{{12}}{2} \cr & = {\text{6 days }} \cr} $$
This Question Belongs to Arithmetic Ability >> Time And Work
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