?
A can finish a piece of work in a certain number of days. B takes 45% more number of days to finish the same work independently. They worked together for 58 days and then the remaining work was done by B alone in 29 days. In how many days could A have completed the work, had he worked alone?
Answer & Solution
Correct Answer:
Option
B
$$\eqalign{
& 45\% = \frac{9}{{20}} \cr
& {\text{Efficiency A}} = 29{\text{ and B}} = 20 \cr
& 58 \times 49 + 29 \times 20 = 3422 \cr
& {\text{Required answer A}} = \frac{{3422}}{{29}} = 118\,{\text{days}} \cr} $$
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