A capacitance of 250 pF produces resonance with a coil at a frequency of $$\frac{2}{\pi } \times {10^6}\,{\text{Hz,}}$$ while at the second harmonic of this frequency, resonance is produced by a capacitance of 50 pF the coil will be nearly
A. 16.7 pF
B. 20.5 pF
C. 24.3 pF
D. 28.1 pF
Answer: Option A
This Question Belongs to Electronics And Communications Engineering >> Measurement And Instrumentation
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