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A child went 90 m in the East to look for his father, then he turned right and went 20 m. After this he turned right and after going 30 m he reached to his uncle's house. His father was not there. From there he went 100 m to his north and met his father. How far did he meet his father from the starting point?
Answer & Solution
Correct Answer:
Option
B

Required Distance
= AE
= √(AG2 + EG2)
= √{(90 - 30)2 + (100 - 20)2}
= √{(60)2 + (80)2}
= √(3600 + 6400)
= √10000
= 100 m
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