A dishonest dealer marks up the price of his goods by 20% and gives a discount of 10% to the customer. Besides, he also cheats both his supplier and his buyer by 100 grams while buying or selling 1 kilogram. Find the percentage profit earned by the shopkeeper?
A. 20%
B. 25%
C. 32%
D. 46.66%
E. 50%
Answer: Option C
Solution(By Examveda Team)
While buying,He buys 1100 gram instead of 1000 gram.
Suppose he bought 1100 grams for Rs. 1000.
While selling, He sells only 900 grams when he takes the money for 1 kg. Now, according to the problem, he sells at a 8% profit (20% markup, 10% discount). Hence, his selling price is Rs. 1080 for 900 grams. Now, 1100 grams for Rs. 1000 Hence, 1188 grams for Rs. 1080 Selling: 900 grams for Rs. 1080 Hence, % profit = $$\frac{{288}}{{900}}$$ × 100 = 32% (using goods left by goods sold formula).
Join The Discussion
Comments ( 13 )
Related Questions on Profit and Loss
A. 45 : 56
B. 45 : 51
C. 47 : 56
D. 47 : 51
A. Rs. 2600
B. Rs. 2700
C. Rs. 2800
D. Rs. 3000
A. A neither losses nor gains
B. A makes a profit of 11%
C. A makes a profit of 20%
D. B loses 20%
A. Rs. 3,750
B. Rs. 3,250
C. Rs. 2,750
D. Rs. 2,250
Let CP = 100
MP = 120
SP = 120 - 10% of 120 = 108.
now, he buys 1100 gram instead of 1000 gram.
so, CP of 1gm = 100/1100 = 1/11
He sells only 900 grams at the money for 1 kg
so, SP of 1gm = 108/900 = 3/25
so, gain = 3/25 - 1/11 = 8/275
Therefore, gain % = (gain/cp) *100 = [(8/275)/(1/11)] *100 = (8/25)*100 = 800/25 = 32
so gain is 32%
Let C.P=100
S.P=100*120/100*90/100*110/100*100/90=132
✓p%=S.P-C.P=132-100=32
Hence 32%P
100×(6/5)×(9/10)×(11/10)×(10/9) = 132
∴ Profit% = (132 - 100) = 32%
Applying multiplying factor concept :
100*(6/5)*(9/10)*(11/10)*(10/9)= 132
So, profit = (132-100) = 32%
120×90×1000×1100/100×100×900×1000=32%
Price increased by 20% it mean 120 and he gives discount 10% so it become 90 then he cheat by 100gm while buying and selling ,in buying it become 1100 and in selling it become 900 so it gives 32%
How 1080 came
How 1188 came
@Bhavya
Let CP = 100
MP = 100 + 20% of 100 = 120
SP = 120 - 10% of 120 = 108.
Profit % = (8 *100)/100 = 8%.
This is a simple assumption.
Formula for calculating profit% when discount and m.p given ..
P%= m%-d%-md/100
So
P%= 20-10-200/100
= 8%
A shopkeeper marks up the price of his product by 40%. If he increases the discount from 5% to 10% ,the pro�t would decrease by Rs 14. How much pro�t would he earn if he gives a discount of 20% on the marked price?
can anyone.. pls expl the best way to solve the problem
A group of students prepared stuffed toys as part of their group activity. They spent Rs. 100 on velvet, Rs 5 on thread and needle and Rs. 27 on miscellaneous items. They made 30 toys, 50% of which were purchased by force by some senior students causing them a loss of50%. At what % pro�t should they sell the remaining toys so as to gain 50% on their total cost?
pls expl
Solution: Let when buying-- 1100 gm at Rs. 1000 when selling-- 900 gm at Rs. 1080 [20% mark up & 10% discount] so, the selling price of 1100 gm =Rs. (1080*1100)/900 =Rs. 1320 Profit%= (320*100)/1000= 32%
how did u calculate the profit percent when discount and mark up percent were given