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A dishonest dealer purchases goods at 20% discount of the cost price of Rs. X and also cheats his wholesaler by getting 20% extra through false weighing, per kg. Then he marks up his goods by 80% of x, but he gives a discount of 25% besides he cheats his customer by weighing 10% less than the required. What is his overall profit percentage?

A. 125%

B. 100%

C. 98.66%

D. 120%

E. None of these

Answer: Option A

Solution(By Examveda Team)

Let actual cost price of an article be Rs. 1 (in place of X). Now he purchases goods worth Rs. 120 and pays Rs. 80, since 20% discount is allowed.
So, the CP = $$\frac{{80}}{{120}} = \frac{2}{3}$$
Again, MP, SP = 135 (since 25% discount)
Thus, the trader sells goods worth Rs. 90 instead of 100g and charges Rs. 135.
Therefore the effective SP = $$\frac{{135}}{{90}} = \frac{3}{2}$$
$$\eqalign{ & {\text{Profit}}\,\% \cr & = {\frac{{ { {\frac{3}{2}} - {\frac{2}{3}} } }}{{\frac{2}{3}}}} \times 100 \cr & = 125\% \cr} $$

This Question Belongs to Arithmetic Ability >> Profit And Loss

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Comments ( 2 )

  1. Prashant Kumar
    Prashant Kumar :
    7 years ago

    can anyone solve this with short trick ?

  2. Kumar Chandan
    Kumar Chandan :
    7 years ago

    He gets 20% discounts and as well he cheats 20% as well.
    Let 1000 was the actual CP.
    Now, in 800 he gets 1200g. Means his cost of 1200g is 800.
    So, his CP for 900,
    = (800*900)/1200 = 600.
    MP = 1000 + 80% of 1000 = 1800
    SP = 1800 - 25% of 1800 = 1350.
    1350 is for 900g.
    Thus total gain = 450 + 300 = 750
    % gain = (750*100)/600 = 125%

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