A fruit seller buys some oranges and by selling 40% of them he realizes the cost price of all the oranges. As the oranges being to grow over-ripe, he reduces the price and sells 80% of the remaining oranges at half the previous rate of profit. The rest of the oranges being rotten are thrown away. The overall percentage of profit is:
A. 80
B. 84
C. 94
D. 96
Answer: Option B
Solution(By Examveda Team)
Let fruit seller buys 100 oranges for Rs. 100 On selling of 40% of the oranges he realizes his cost price i.e. He sells 40 oranges for Rs. 100 Profit on 40 Oranges = 100 - 40 = Rs. 60 % profit on 40 oranges = $$\frac{{60 \times 100}}{{40}}$$ = 150% Now, he sells 80% of 60 oranges on half of the previous profit i.e. 48 oranges, he sells at 75% of profit So, SP of 48 oranges = 48 + 75% of 48 = 84 12 was rotten so he threw away. Total SP = 100 + 84 = Rs. 184 Profit = 184 - 100 = 84 %Profit = 84%This Question Belongs to Arithmetic Ability >> Profit And Loss
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Let, Total oranges are 100 and CP of 1 orange 1 Tk. (Total CP 100 Tk.)
SP of 40% oranges are 100 (Here CP of 40 oranges are 40 Tk.)
Profit% = 60*100/40 = 150%
Remaining oranges are 60
SP of 80% oranges Of 60 = 48 (Here CP of 48 oranges ar 48 Tk.)
SP of 48 oranges = 48*(7/4) = 84 Tk.
So Total SP = ( 100 + 84 ) = 184 Tk.
Profit% = 100*84/100 = 84%
Could anyone explain??
Profit on first selling= 100-40= 60
Further, profit on 48 oranges= 84-48=36
Overall profit =60+36= 96
%Profit= 96/100×100=96%
Am i doing something wrong???
12 oranges were rotten. this means he sold only 88 oranges. hence SP per orange should be Rs 184/88 and CP per orange as Re 1. that gives the answer as (109 + 1/11)%
Really a superb solution...hats off
where it is mentioned that he sells 40% at cost price, how u can say he sells 40 fruit at 100???
Thanks a lot for the solution.
He has 150% of profit on the transaction of 40% of oranges.
And now he is selling 80% of 60 oranges on half of the previous profit. I.e.
Earlier profit was 150% then half profit of 150% would be 75%.
75% how comes please explain