A man bought a horse and a cart. If he sold the horse at 10 % loss and the cart at 20 % gain, he would not lose anything; but if he sold the horse at 5% loss and the cart at 5% gain, he would lose Rs. 10 in the bargain. The amount paid by him was Rs._______ for the horse and Rs.________ for the cart.
A. 500, 300
B. 200, 400
C. 400, 200
D. 300, 500
Answer: Option C
Solution(By Examveda Team)
Let X be the cost of horse and Y be the cost of the cart. 10% of loss in selling horse = 20% of gain in selling the cart. Therefore, $$\frac{{10}}{{100}} \times {\text{X}}$$ = (20 × 100) × Y Or, X = 2y --------------(1) 5% of loss in selling horse is 10 more than the 5% gain in selling the cart. Therefore, $$\frac{5}{{100}} \times {\text{X}} - 10 = \frac{5}{{100}} \times {\text{Y}}$$ => 5X – 1000 = 5Y Using equation (1), => 10Y – 1000 = 5Y => 5Y = 1000 => Y =200 => X = 400 CP of Horse = Rs. 400 CP of the Cart = Rs. 200Related Questions on Profit and Loss
A. 45 : 56
B. 45 : 51
C. 47 : 56
D. 47 : 51
A. Rs. 2600
B. Rs. 2700
C. Rs. 2800
D. Rs. 3000
A. A neither losses nor gains
B. A makes a profit of 11%
C. A makes a profit of 20%
D. B loses 20%
A. Rs. 3,750
B. Rs. 3,250
C. Rs. 2,750
D. Rs. 2,250
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