A man buys a chair and table for Rs. 6000. He sells the chair at a loss of 10% and the table at gain of 10%. He still gains Rs. 100 on the whole. Cost price of chair is:
A. Rs. 2500
B. Rs. 2850
C. Rs. 3050
D. Rs. 3500
Answer: Option A
Solution(By Examveda Team)
If the CP of the chair be Rs. x then, Total SP = $$\frac{{{\text{x}} \times 90}}{{100}}$$ + $$\left( {\left( {6000 - {\text{x}}} \right) \times \frac{{110}}{{100}}} \right)$$ Or, 9x + 66000 - 11x = 61000 Or, 2x = 66000 - 61000 = 5000 Or, x = Rs. 2500This Question Belongs to Arithmetic Ability >> Profit And Loss
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Comments ( 2 )
Related Questions on Profit and Loss
A. 45 : 56
B. 45 : 51
C. 47 : 56
D. 47 : 51
A. Rs. 2600
B. Rs. 2700
C. Rs. 2800
D. Rs. 3000
A. A neither losses nor gains
B. A makes a profit of 11%
C. A makes a profit of 20%
D. B loses 20%
A. Rs. 3,750
B. Rs. 3,250
C. Rs. 2,750
D. Rs. 2,250
Chair + Table =6000
chair * 90/100 + Table * 110/100 = 6100
9chair + 11table = 61000 (eq 1)
We know Chair +Table = 6000 ---> (eq 2) And we want to calculate Price of chair hence to remove table from eq 1 multiply eq2 with 11 --> 11chair + 11 table = 66000
9chair + 11table = 61000
11chair+11table =66000
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2Chair+0 = 5000
chair = 5000/2 ---------> 2500 Rs
Sir any easy method please tell