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A man is twice as fast as a women and a woman is twice as fast as a boy in doing a work. If all of them, a man , a woman and a boy can finish the work in 7 days, a boy will do it alone ?
Answer & Solution
Correct Answer:
Option
A
| Man | : | Woman | : | Boy | |
| Efficiency | 4 | : | 2 | : | 1 |
Total work = Time × (Efficiency of man + woman + boy)
⇒ 7 days × (4 + 2 + 1) = 49 units
∴ Boy can do this work in = $$\frac{{49}}{1}$$ = 49 days
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