A man sells an article at 10% loss. If he had sold it at Rs. 10 more, he would have gained 10% . The cost price of the article is = ?
A. Rs. 50
B. Rs. 55
C. Rs. 100
D. Rs. 110
Answer: Option A
Solution(By Examveda Team)
Let the CP1 of Article= 100xInitial SP1 = 100x - 10% of 100x = 100x - 10x = 90x
If He sold the Article 10% profit
Now SP2 = 100x + 10% of 100x = 100x + 10x =110x
According to question
SP2 - SP1 = 10
⇒ 110x - 90x = 10
⇒ 20x = 10
⇒ x = $$\frac{1}{2}$$
Initial Cost of Article = 100 × $$\frac{1}{2}$$ = Rs. 50
This Question Belongs to Arithmetic Ability >> Profit And Loss
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Related Questions on Profit and Loss
A. 45 : 56
B. 45 : 51
C. 47 : 56
D. 47 : 51
A. Rs. 2600
B. Rs. 2700
C. Rs. 2800
D. Rs. 3000
A. A neither losses nor gains
B. A makes a profit of 11%
C. A makes a profit of 20%
D. B loses 20%
A. Rs. 3,750
B. Rs. 3,250
C. Rs. 2,750
D. Rs. 2,250
Let the cp be rs. 100
So when cp=100, loss 10% means Sp1=100-10=90
Profit of 5% means sp2=100+10=110
(The difference of sp1&sp2=110-90=20)
If the difference is rs10 cp=100/20*10=50