ExamVeda
Login
Home

A particle is moving under the action of a generalised potential...

This question belongs to Engineering Physics Classical Mechanics
Classical Mechanics
?

A particle is moving under the action of a generalised potential $$V\left( {q,\,\dot q} \right) = \frac{{\left( {1 + \dot q} \right)}}{{{q^2}}}$$
The magnitude of generalised force is

Answer & Solution
Correct Answer: Option A
Let's discuss the solution. Join the discussion
Examveda
Question posted by Examveda
Community

Join the Discussion

No comments yet Be the first to discuss this question.
Keep Learning

Related Questions on Classical Mechanics

A mass m is constrained to move on a horizontal frictionless surface. It is set in circular motion with radius r0 and angular speed ω0 by an applied force $$\overrightarrow {\bf{F}} $$ communicated through an inextensible thread that passesthrough a hole on the surface as shown in figure given below. Then, this force is suddenly doubled.
Classical Mechanics mcq question image
The magnitude of the radial velocity of the mass
A. increases till mass falls into hole B. decreases till mass falls into hole C. remains constant D. becomes zero at radius r1, where 0 < r1 < r0
The speed of a particle whose kinetic energy is equal to its rest mass energy, is given by (c is the speed of light in vacuum)
A. $$\frac{c}{3}$$ B. $$\frac{{\sqrt 2 }}{3}c$$ C. $$\frac{c}{2}$$ D. $$\frac{{\sqrt 3 }}{2}c$$
The Hamiltonian corresponding to the Lagrangian $$L = a{{\dot x}^2} + b{{\dot y}^2} - kxy$$     is
A. $$\frac{{{p_x}^2}}{{2a}} + \frac{{{p_y}^2}}{{2b}} + kxy$$ B. $$\frac{{{p_x}^2}}{{4a}} + \frac{{{p_y}^2}}{{4b}} - kxy$$ C. $$\frac{{{p_x}^2}}{{4a}} + \frac{{{p_y}^2}}{{4b}} + kxy$$ D. $$\frac{{{p_x}^2 + {p_y}^2}}{{4ab}} + kxy$$
A particle is moving in an inverse square field. If the total energy of the particle is positive, then trajectory of particle is
A. circular B. elliptical C. parabolic D. hyperbolic
More Related Questions on Classical Mechanics