A shopkeeper purchases two items for Rs. 520. One of them is sold gaining 16% and the other at a loss of 10%, thus making no profit or loss. What is the selling price of the item sold at loss ?

Solution(By Examveda Team)

Let the price of 1^st item is x
Then for 2^nd 520 - x
Profit and loss of both items are same
Then,
$$\eqalign{ & \frac{{x \times 16}}{{100}} - \frac{{\left( {520 - x} \right) \times 10}}{{100}} = 0 \cr & \Rightarrow 16x = \left( {520 - x} \right)10 \cr & \Rightarrow 26x = 5200 \cr & \Rightarrow x = 200 \cr & {\text{CP}} = 520 - 200 \cr & \,\,\,\,\,\,\,\,\,\,\, = 320 \cr & {\text{SP}} = 320 \times \frac{{90}}{{100}} \cr & \,\,\,\,\,\,\,\,\,\, = 288 \cr} $$