A shopkeeper sells guava worth 22 per kg to Anand and Sakshi for Rs. 25 each. He sold Anand 950 g instead of 1 kg. He sold the 'x' gm to Sakshi instead of 1 kg using a defective weight. If he earns a real profit of Rs. 7.76 by selling both, then what is the value of 'x'?
A. 970 g
B. 980 g
C. 960 g
D. 985 g
Answer: Option A
Solution(By Examveda Team)
Total profit = 7.76In Ist case, (Anand) instead of 1 kg, he gave 950 gm
So, profit = 50 gm
⇒ 1000 gm = Rs. 22
1 gm = $$\frac{{22}}{{1000}}$$
50 gm = $$\frac{{1100}}{{1000}}$$ = 1.1
In Ist case, total profit = 3 + 1.1 = Rs. 4.1
So, left profit = 7.76 - 4.1 = Rs. 3.66
In IInd case, (Sakshi) profit is Rs. 3 as he sold (in Rs. 25) and left Rs. 0.66 is because he sold less of instead of 1000 gm
So, Rs. 22 → 1000 gm
Rs. 1 → $$\frac{{1000}}{{22}}$$ × 0.66 = 30 gm
So he sold 970 gm instead of 1000 gm Answer
Related Questions on Profit and Loss
A. 45 : 56
B. 45 : 51
C. 47 : 56
D. 47 : 51
A. Rs. 2600
B. Rs. 2700
C. Rs. 2800
D. Rs. 3000
A. A neither losses nor gains
B. A makes a profit of 11%
C. A makes a profit of 20%
D. B loses 20%
A. Rs. 3,750
B. Rs. 3,250
C. Rs. 2,750
D. Rs. 2,250
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