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A showroom owner sells a leather jacket for Rs. x and claims to make a profit of 10%. He plans to have a stall in the trade fair and marks the same jacket at Rs. 2x. At the stall,he allows a discount of 20%. What will be the percentage profit that he will make at the trade fair?

A. 60%

B. 76%

C. 80%

D. 86%

Answer: Option B

Solution(By Examveda Team)

$$\eqalign{ & {\text{S}}{\text{.P}}{\text{. = Rs}}{\text{. }}x \cr & {\text{Profit = 10}}\% \cr & {\text{C}}{\text{.P}}{\text{. = Rs}}{\text{.}}\left( {\frac{{100}}{{110}} \times x} \right) \cr & \,\,\,\,\,\,\,\,\,\,\,\,\, = {\text{ Rs}}{\text{.}}\frac{{10x}}{{11}} \cr & {\text{M}}{\text{.P}}{\text{. = Rs}}{\text{. }}2x, \cr & {\text{Discount = 20}}\% {\text{}} \cr} $$
S.P. at trade fair = 80% of Rs. 2x
$$\eqalign{ & {\text{ = Rs}}{\text{.}}\left( {\frac{{80}}{{100}} \times 2x} \right) \cr & = {\text{Rs}}{\text{.}}\frac{{8x}}{5} \cr & {\text{Profit = Rs}}{\text{.}}\left( {\frac{{8x}}{5} - \frac{{10x}}{{11}}} \right) \cr & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = {\text{Rs}}{\text{.}}\frac{{38x}}{{55}} \cr & \therefore {\text{ Profit }}\% \cr & {\text{ = }}\left( {\frac{{38x}}{{55}} \times \frac{{11}}{{10x}} \times 100} \right)\% \cr & = 76\% \cr} $$

This Question Belongs to Arithmetic Ability >> Profit And Loss

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Comments ( 1 )

  1. Vaibhav Shekhar
    Vaibhav Shekhar :
    2 years ago

    Let CP =100 , Profit =10%
    It means Rs x = 110%
    Discount =20%
    Sp = 80% of 2x =1.6x
    1.6x =110*1.6 = 176 which symbolises 76% profit.

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