A source produces 4 symbols with probabilities $$\frac{1}{2}$$, $$\frac{1}{4}$$, $$\frac{1}{8}$$ and $$\frac{1}{8}$$. For this source, a practical coding scheme has an average code word length of 2 bits/symbol. The efficiency of the code is:

A. The same as FDM B. The same as TDM C. A combination of FDM and TDM D. Quite different from FDM and TDM

A. C₂ ≈ 2C₁ B. C₂ ≈ C₁ + B C. C₂ ≈ C₁ + 2B D. C₂ ≈ C₁ + 0.3B

A. 1 and 2 B. 2 and 3 C. 1 and 3 D. None of the above

A. Maximum Likelihood Decoding B. Sequential Decoding C. Both A and B D. None of the above