A spider climbed $$\frac{{125}}{2}$$ % of the height of the pole in one hour and in the next hour it covered $$\frac{{25}}{2}$$ % of remaining height. If pole's height is 192 m, then distance climbed in second hour is:

Solution (By Examveda Team)

$$\eqalign{ & {\text{Height}}\,{\text{of}}\,{\text{the}}\,{\text{Pole}} = 192\,m. \cr & {\text{Spider}}\,{\text{covered}}\,{\text{in}}\,{\text{first}}\,{\text{hour}}, \cr & = \frac{{125}}{2}\% \,of\,192 \cr & = \frac{{ {125 \times 192} }}{{ {2 \times 100} }} \cr & = 120\,m \cr & {\text{Remaining Pole}} = 192 - 120 = 72\,m \cr & {\text{Spider}}\,{\text{covered}}\,{\text{in}}\,{\text{second}}\,{\text{hour}}, \cr & = \frac{{25}}{2}\% \,{\text{of}}\,{\text{ remaining}}\,{\text{ height}} \cr & = \frac{{ {25 \times 72} }}{{ {2 \times 100} }} \cr & = 9\,m \cr} $$