A string of length 221 metre is cut into two parts such that one part is $$\frac{9}{4}$$ th as long as the rest of the string, then the difference between the larger piece and the shorter piece is :

A. 58 m

B. 53 m

C. 85 m

D. 76 m

Answer: Option C

Solution(By Examveda Team)

Let one part of string is x.
Now,
x + $$\frac{{9{\text{x}}}}{4}$$ = 221 m
x = 68 meter
and, $$\frac{{9{\text{x}}}}{4}$$ = 153 m
Difference between two parts = 153 - 68 = 85m.