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A student got twice as many sums wrong as he got...

This question belongs to Competitive Reasoning Arithmetic Reasoning
Arithmetic Reasoning
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A student got twice as many sums wrong as he got right. If he attempted 48 sums in all, how many did he solve correctly ?

Answer & Solution
Correct Answer: Option B
Suppose the boy got x sums right and 2x sums wrong.
Then, x + 2x = 48 ⇔ 3x = 48 ⇔ x = 16.
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