A student got twice as many sums wrong as he got right. If he attempted 48 sums in all, how many did he solve correctly ?
A. 12
B. 16
C. 18
D. 24
Answer: Option B
Solution(By Examveda Team)
Suppose the boy got x sums right and 2x sums wrong.Then, x + 2x = 48 ⇔ 3x = 48 ⇔ x = 16.
This Question Belongs to Competitive Reasoning >> Arithmetic Reasoning
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