A team of 8 students goes on an excursion, in two cars, of which one can seat 5 and the other only 4. In how many ways can they travel?
A. 392
B. 126
C. 26
D. 9
Answer: Option B
Solution(By Examveda Team)
There are 8 students and the maximum capacity of the cars together is 9. We may divide the 8 students as follows:Case I: 5 students in the first car and 3 in the second. Hence, 8 students are divided into groups of 5 and 3 in 8C3 = 56 ways.
Case II: 4 students in the first car and 4 in the second. So, 8 students are divided into two groups of 4 and 4 in 8C4 = 78 ways. Therefore, the total number of ways in which 8 students can travel is: 56 + 70 = 126
8C5 + 8C4 = 58+70 = 126