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A traders sells two acrticles one at a loss of 10...

This question belongs to Arithmetic Ability Profit And Loss
Profit and Loss
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A traders sells two acrticles, one at a loss of 10% and another at a profit of 15% but finally there is no loss or gain. If the total sale price of these two articles is Rs. 30,000, find the difference between their cost prices:

Answer & Solution
Correct Answer: Option B
10% of x = 15 % of y, where x + y = 30000
$$\frac{{\text{x}}}{{\text{y}}} = \frac{{3{\text{k}}}}{{2{\text{k}}}}$$
Hence, difference = k = Rs. 6000
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6 Comments
KAVIYA C
KAVIYA C 2 years ago
10/100*x=15/100*y
Ratio is 2x:3y and x:y is 3:2
The total so x+y=30000
also x:y=3k:2k
x+y means 3k+2k=5k
So 5k=30000
k=6000
Sam Sammy
Sam Sammy 6 years ago
10% of x = 15% of y
x/y=3/2.
x+y=30000.
x=18000,y=12000.
x=0.9Cp1.
y=1.15Cp2.
Cp1=19800.
Cp2=10200.
Diff. Cp1-Cp2=9600.
Sam Sammy
Sam Sammy 6 years ago
In the question they asked difference between their cost prices but here two selling prices substracted. Anyone please tell me if I'm wrong
Aman Upadhyay
Aman Upadhyay 6 years ago
Try to solve it with ratios P:L = 3:2, 30000 = 18000 : 12000 (3:2), Difference = 6000
Naavin RS
Naavin RS 8 years ago
From the question
10 % x = 15% of y ...(i)
x+y = 30000 ...(ii)

from eq. (i)
x / y = 3/2 ...(iii)

by solving eq. (ii) & (iii) 
x = 18000, y = 12000

Hence, the difference =6000
Krishna Potala
Krishna Potala 8 years ago
another way to solve the problem please

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