A tradesman marks his goods at 25% above the cost price and allows purchasers a discount of $$\frac{{25}}{2}$$%, his profit is:
A. 8%
B. 8.5%
C. 8.625%
D. 9.375%
Answer: Option D
Solution(By Examveda Team)
Let his CP = Rs. 100.
Marked Price = 100 + 25% of 100 = 125.
Now, discount = $$\frac{{25}}{2}$$% on MP
So, SP = 125 - $$\frac{{25}}{2}$$% of 125 = Rs. 109.375.
%Gain = 9.375%.
Alternatively use graphic change method:
100(CP) == 25% Up ⇒ 125(MP) == 12.5%down ⇒ 109.375
%Profit = 9.375%
This Question Belongs to Arithmetic Ability >> Profit And Loss
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Related Questions on Profit and Loss
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D. 47 : 51
A. Rs. 2600
B. Rs. 2700
C. Rs. 2800
D. Rs. 3000
A. A neither losses nor gains
B. A makes a profit of 11%
C. A makes a profit of 20%
D. B loses 20%
A. Rs. 3,750
B. Rs. 3,250
C. Rs. 2,750
D. Rs. 2,250
Let the cost price be Rs 100.
Then, marked price = Rs 125.
Discount = 12.5% of Marked Price
= (12.5% of Rs 125)
= Rs {125 × (12.5/100)
= Rs 15.625.
Selling price = (marked price) - (discount)
= Rs (125 - 15.625)
= Rs 109.375.
Gain% = (109.375 - 100) % = 9.375%.
Hence, the trader gains 5%.
CP=80
MP=100
Now.. 100- (25/2)% of 100=87.5
Profit=7.5
Profit%= (7.5/80)*100= 9.375%.
.Done
Ans is not coming if we take the CP= 80 and MP will become 100.
Now, 100- (25/2)% of 100=87.5
please explain this sum