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A train B speeding with 120 kmph crosses another train C running in the same direction, in 2 minutes. If the lengths of the trains B and C be 100m and 200m respectively, what is the speed (in kmph) of the train C?

A. 111 km

B. 123 km

C. 127 km

D. 129 km

Answer: Option A

Solution(By Examveda Team)

$$\eqalign{ & {\text{Relative speed of the trains }} \cr & {\text{ = }}\left( {\frac{{100 + 200}}{{2 \times 60}}} \right){\text{m/sec}} \cr & {\text{ = }}\left( {\frac{5}{2}} \right){\text{m/sec}} \cr & {\text{Speed of train B}} \cr & {\text{ = 120 kmph}} \cr & = \left( {120 \times \frac{5}{{18}}} \right){\text{m/sec}} \cr & {\text{ = }}\left( {\frac{{100}}{3}} \right){\text{m/sec}} \cr & {\text{Let the speed of second train be }}x{\text{ m/sec}} \cr & {\text{Then, }} \frac{{100}}{3} - x = \frac{5}{2} \cr & \Rightarrow x = \left( {\frac{{100}}{3} - \frac{5}{2}} \right) \cr & \,\,\,\,\,\,\,\,\,\,\,\,\,\, = \left( {\frac{{185}}{6}} \right){\text{m/sec}} \cr & \therefore {\text{Speed of second train}} \cr & {\text{ = }}\left( {\frac{{185}}{6} \times \frac{{18}}{5}} \right){\text{ kmph}} \cr & {\text{ = 111 kmph}} \cr} $$

This Question Belongs to Arithmetic Ability >> Problems On Trains

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Comments ( 3 )

  1. Atishay Singhai
    Atishay Singhai :
    4 years ago

    Speed = distance / time
    s1 -s2 = x+y/t
    120-s2 = 100+200/ 2×60
    120-s2 =300/120
    120-s2 = 5/2
    120-s2 = 5/2 × 18/5
    120-s2 =9
    s2 = 120-9
    s2 =111 kmph is answer

  2. Mehedi Mitun
    Mehedi Mitun :
    5 years ago

    Ans should be 111

  3. Riasat Ali
    Riasat Ali :
    5 years ago

    How can the speed of train C be greater than the B's as B crosses C? The equation will be, 100/3-x=5/2
    Hence, x=111
    Correct it.
    Thanks

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