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ab(a - b) + bc(b - c) + ca(c - a)...

This question belongs to Arithmetic Ability Algebra
Algebra
?

ab(a - b) + bc(b - c) + ca(c - a) is equal to:

Answer & Solution
Correct Answer: Option C
ab(a - b) + bc(b - c) + ca(c - a)
Let c = 0
ab(a - b)
Now from option C
(b - a)(b - c)(c - a)
= -(a-b)b(-a)
= ab(a - b)
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