According to Bond crushing law, the work required to form particle of size 'D' from very large feed is (where $${\left( {\frac{{\text{S}}}{{\text{V}}}} \right)_{\text{p}}}$$ and $${\left( {\frac{{\text{S}}}{{\text{V}}}} \right)_{\text{f}}}$$ are surface to volume ratio of the product and feed respectively).

A. $${\left( {\frac{{\text{S}}}{{\text{V}}}} \right)_{\text{p}}}$$

B. $$\sqrt {{{\left( {\frac{{\text{S}}}{{\text{V}}}} \right)}_{\text{p}}}} $$

C. $$\left( {\frac{{\text{S}}}{{\text{V}}}} \right)_{\text{p}}^2$$

D. $${\left( {\frac{{\text{S}}}{{\text{V}}}} \right)_{\text{f}}}$$

Answer: Option B