An article costing Rs. 20 was marked 25% above the cost price. After two successive discounts of the same percentage, the customer now pays Rs. 20.25. What would be the percentage change in profit had the price been increased by the same percentage twice successively instead reducing it?
A. 3600%
B. 3200%
C. 2800%
D. 4000%
E. 3800%
Answer: Option D
Solution(By Examveda Team)
The successive discounts must have been of 10% each As20 (CP) == 25%↑ ⇒ 25(MP) == 10↓ ⇒ 22.5 == 10%↓ ⇒ 20.25(SP)
Profit = 20.25 - 20 = 0.25
Increased percentage if price have been increased twice successively instead of reducing it,
20(MP) == 10%↑ ⇒ 27.5 == 10%↑ ⇒ 30.25
Profit = 30.25 - 20 = 10.25.
Profit Change = 10.25 - 0.25 = 10
Percentage Profit change,
= $$\frac{{10 \times 100}}{{0.25}}$$
= 4000%
This Question Belongs to Arithmetic Ability >> Profit And Loss
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Comments ( 4 )
Related Questions on Profit and Loss
A. 45 : 56
B. 45 : 51
C. 47 : 56
D. 47 : 51
A. Rs. 2600
B. Rs. 2700
C. Rs. 2800
D. Rs. 3000
A. A neither losses nor gains
B. A makes a profit of 11%
C. A makes a profit of 20%
D. B loses 20%
A. Rs. 3,750
B. Rs. 3,250
C. Rs. 2,750
D. Rs. 2,250
Let, Successive discount 10%
First condition :
Applying multiplying factor concept :
20*(5/4)*(9/10)*(9/10) = 20.25 (SP₁)
Profit = .25
Second condition :
Applying multiplying factor concept :
20*(5/4)*(11/10)*(11/10) = 30.25 (SP₂)
Profit = (30.25 - 20 ) = 10.25
Diff. profit = (10.25 - 0.25 ) = 10
Diff. profit% = (10*100)/0.25 = 4000%
Solved by : Md. Helal Uddin
25x^2
.............. = 20.25
100*100
x^2 = 8100
x = 90
discount = 100-90 = 10%
SP=25*110%^2 = 30.25
P2 = 30.25-20=10.25
P1 = 20.25-20=0.25
% CHANGE IN PROFIT..............
10.25-0.25 = 10
10*100/0.25 = 4000%
How did the precentage change in profit reach 4000%?
can we have any better solution??