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An employee pays Rs. 26 for each day a worker and forfeits Rs. 7 for each day he idle. At the end of 56 days, if the worker got Rs. 829, for how many days did the worker remain idle?

A. 21

B. 15

C. 19

D. 13

E. 17

Answer: Option C

Solution(By Examveda Team)

His Per day pay = Rs. 26
Total pay employee got = Rs. 829
Total pay he gets if he did not remain idle a single day,
= 26 × 56 = Rs.1456
He Forfeits or fined = 1456 - 829 = Rs. 627
Per day he Forfeits Rs. 7 Means per idle day he loses = 26 + 7 = Rs. 33
So, Total idle days = $$\frac{{627}}{{33}}$$ = 19 days

Alternatively,
Let he works for X days and remain idle for (56 - X)
Now, According to question,
X × 26 - 7 × (56 - X) = 829
26X + 7X - 392 = 829
33X = 829 + 392 = 1221
X = 37 days
Number of days remain idle = 56 -37 =19 days

This Question Belongs to Arithmetic Ability >> Time And Work

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