An employee pays Rs. 26 for each day a worker and forfeits Rs. 7 for each day he idle. At the end of 56 days, if the worker got Rs. 829, for how many days did the worker remain idle?
A. 21
B. 15
C. 19
D. 13
E. 17
Answer: Option C
Solution(By Examveda Team)
His Per day pay = Rs. 26 Total pay employee got = Rs. 829 Total pay he gets if he did not remain idle a single day, = 26 × 56 = Rs.1456 He Forfeits or fined = 1456 - 829 = Rs. 627 Per day he Forfeits Rs. 7 Means per idle day he loses = 26 + 7 = Rs. 33 So, Total idle days = $$\frac{{627}}{{33}}$$ = 19 days Alternatively, Let he works for X days and remain idle for (56 - X) Now, According to question, X × 26 - 7 × (56 - X) = 829 26X + 7X - 392 = 829 33X = 829 + 392 = 1221 X = 37 days Number of days remain idle = 56 -37 =19 daysRelated Questions on Time and Work
A. 18 days
B. 24 days
C. 30 days
D. 40 days
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