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Average - Aptitude MCQ Questions and Solutions with Explanations

Average MCQ Questions and answers with easy and logical explanations.Arithmetic Ability provides you all type of quantitative and competitive aptitude mcq questions on Average with easy and logical explanations. Average MCQ is important for exams like Banking exams,IBPS,SCC,CAT,XAT,MAT etc. Page-6 section-1

Each section contains 100 MCQs on Average .
51
There were 35 students in a hostel. Due to the admission of 7 new students the expenses of the mess were increased by Rs.42 per day while the average expenditure per head diminished by Re 1. What was the original expenditure of the mess?
Discuss
Answer & Solution
Answer: Option D
Solution:
Let the original average expenditure be Rs. x then, 42(x - 1) - 35x = 42
⇒ 7x = 84
⇒ x = 12
Therefore original expenditure,
= Rs. (35 × 12)
= Rs. 420
52
Nine persons went to a hotel for taking their meals. Eight of them spent Rs. 12 each on their meals and the ninth spent Rs. 8 more than the average expenditure of all the nine. What was the total money spent by them.
Discuss
Answer & Solution
Answer: Option C
Solution:
Let the average expenditure of all the nine be x
Then, 12 × 8 + (x + 8) = 9x
Therefore, x = 13
Total money spent,
= 9x
= Rs. (9 × 13)
= Rs. 117
53
David obtained 76, 65, 82, 67 and 85 marks (out of 100) in English, mathematics, physics, chemistry and biology. What are his average marks?
Discuss
Answer & Solution
Answer: Option C
Solution:
$$\eqalign{ & {\text{Average}} \cr & = \frac{{ {76 + 65 + 82 + 67 + 85} }}{5} \cr & = \frac{{375}}{5} \cr & = 75 \cr & {\text{Hence,}}\,{\text{average}} = 75 \cr} $$
54
The average of runs of a cricket player of 10 innings was 32. How many runes must be made in his next innings so as to increase his average of runs by 4?
Discuss
Answer & Solution
Answer: Option D
Solution:
Average after 11 innings = 36
Required number of runs,
= ( 36 × 11) - (32 × 10)
= 396 - 320
= 76
55
There are two sections A and B of a class, consisting of 36 and 44 students respectively. If the average weight of section A is 40kg and that of section B is 35kg, find the average weight of the whole class.
Discuss
Answer & Solution
Answer: Option D
Solution:
Total weight of (36 + 44) Students,
= (36 × 40 + 44 × 35) kg
= 2980 kg
Therefore average weight of the whole class,
= $$ {\frac{{2980}}{{80}}} $$  kg.
Therefore average weight = 37.25 kg.
56
Distance between two stations A and B is 778km. A train covers the journey from A to B at 84km per hour and returns back to A with a uniform speed of 56km per hour. Find the average speed of train during the whole journey.
Discuss
Answer & Solution
Answer: Option D
Solution:
$$\eqalign{ & {\text{Average speed}} \cr & = {\frac{{2xy}}{{ {x + y} }}} {\kern 1pt} {\kern 1pt} {\text{km/hr}} \cr & = {\frac{{ {2 \times 84 \times 56} }}{{ {84 + 56} }}} {\kern 1pt} {\kern 1pt} {\text{km/hr}} \cr & = {\frac{{ {2 \times 84 \times 56} }}{{140}}} {\kern 1pt} {\kern 1pt} {\text{km/hr}} \cr & = 67.2{\kern 1pt} {\kern 1pt} {\text{km/hr}} \cr} $$
57
The average of 50 numbers is 30. If two numbers, 35 and 40 are discarded, then the average of the remaining numbers is nearly:
Discuss
Answer & Solution
Answer: Option B
Solution:
Total sum of 48 numbers,
= (50 × 30) - (35 + 40)
= 1500 - 75
= 1425
Average = $$\frac{{1425}}{{48}}$$ = 29.68
58
The average score of a cricketer for ten matches is 38.9 runs. If the average for the first six matches is 42, then find the average for the last four matches.
Discuss
Answer & Solution
Answer: Option C
Solution:
Total sum of last 4 matches,
= (10 × 38.9) - (6 × 42)
= 389 - 252 = 137
Average = $$\frac{{137}}{4}$$ = 34.25
59
Nine persons went to a hotel for taking their meals. Eight of them spent Rs.12 each on their meals and the ninth spent Rs.8 more than the average expenditure of all the nine. What was the total money spent by them.
Discuss
Answer & Solution
Answer: Option C
Solution:
Let the average expenditure of all the nine be Rs. X
Then, 12 × 8 + (X + 8) = 9X
∴ X = 13 Total money spent = 9X
= Rs. (9 × 13)
= Rs. 117
60
The average of runs of a cricket player of 10 innings was 32. How many runes must be made in his next innings so as to increase his average of runs by 4?
Discuss
Answer & Solution
Answer: Option D
Solution:
Average after 11 innings = 36
Required number of runs
= ( 36 × 11) - (32 × 10)
= 396 - 320
= 76