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1
A sample of 50 litres of glycerine is found to be adulterated to the extent of 20%. How much pure glycerine should be added to it so as to bring down the percentage of impurity to 5% ?
Discuss
Answer & Solution
Answer: Option B
Solution:
Give the amount of solution = 50litres
20% of impurity in a given solution
i.e.
40 liters of glycerine and 10 liters of impurities
Now to keep the impurity 10 liters and we added glycerine to a solution to bring down impurities level 5%.
i.e. 10 is 5% of 200. So we need to added glycerine 'x' amount of glycerine to make solution of 200liters
∴ x = 200 - (40 + 10) = 150 litres of glycerine
2
A and B are two fixed points 5 cm apart and C is a point an AB such that AC is 3 cm. If the length of AC is increased by 6%, the length CB is decreased by :
Discuss
Answer & Solution
Answer: Option D
Solution:
Percentage mcq solution image
After increment of 6% new length of AC
= 3 + $$\frac{3 × 6}{100}$$ = 3.18cm
Required % decrease
= $$\frac{0.18}{2}$$ × 100
= 9%
3
What percentage of the whole week does Ajay spend in office, if his office hours are 9 am to 5 pm from Monday to Friday ?
Discuss
Answer & Solution
Answer: Option B
Solution:
Time spend by Ajoy in a day = 8 hrs
Time spend by Ajay in a week = 8 × 5 = 40 hrs
Percentage time spend in a week :
= $$\frac{40}{24 × 7}$$ × 100
= 23.81%
4
A's salary was decreased by 50% and subsequently increased by 50%. How much percent does he lose ?
Discuss
Answer & Solution
Answer: Option A
Solution:
Let A salary's in starting is = 100
Now after decreased by 50% A salary become = 50
Again 50% of salary increase i.e. 50% of 50 = 25
Current salary is = 50 + 25 = 75
Actual decrease in salary of A = 100 - 75 = 25
Actual % lose = $$\frac{25}{100}$$ × 100 = 25%
5
A man spend $$7\frac{1}{2}$$% of his money and after spending 75% of the remaining he had Rs. 370 left. How much money did he have :
Discuss
Answer & Solution
Answer: Option B
Solution:
Let the 100unit is the salary of the person
After spending 7.5% of his salary remain salary 92.5 Now again he spended 75% of 92.5 and remain 25% which have value Rs. 370
According to the question,
92.5 × 25% unit = 370
92.5 × $$\frac{1}{4}$$ unit = 370
1 unit = $$\frac{370 × 4}{92.5}$$
100 unit = $$\frac{370 × 4 × 100}{92.5}$$
              = Rs. 1600
6
A man spends a part of his monthly income and saves the rest. The ratio of his expenditure to the saving is 61 : 6. If his monthly income is Rs. 8710, the amount of his monthly savings is :
Discuss
Answer & Solution
Answer: Option D
Solution:
Expense + Saving = Income
      61     +     6     =     67
67 units = Rs. 8710
1 unit = $$\frac{{8710}}{{67}}$$  = 130
6 unit = Rs. 780
7
A number is increased by 15% and then decreased by 25% and the number becomes 22 less than the original number. The original number is :
Discuss
Answer & Solution
Answer: Option B
Solution:
Let the number is = 100x
Now after 15% of increase = 100x + 15% of 100x = 115x
Now 25% decrease = 115x - 25% of 115x = 115x - 28.75x = 86.25x
Actual decreased = 100x - 86.25x = 13.75x
According to the question,
13.75x = 22
x = $$\frac{22}{13.75}$$
100x = $$\frac{22}{13.75}$$   × 100 = 160
∴ Original number = 160
8
What is the difference between 0.6 and 0.6% ?
Discuss
Answer & Solution
Answer: Option B
Solution:
0.6% = $$\frac{0.6}{100}$$ = 0.006
So, difference = 0.6 - 0.006 = 0.594
9
A number is decreased by 10% and the resulting number is again decreased by 20%. What is the final percentage of decrease ?
Discuss
Answer & Solution
Answer: Option D
Solution:
Find decreased profit
= 10 + 20 - $$\frac{10 × 20}{100}$$
= 30 - 2
= 28%
10
In an office, 40% of the staff is female. 70% of the female staff and 50% of the male staff are married. The percentage of the unmarried staff in the office is :
Discuss
Answer & Solution
Answer: Option B
Solution:
Let the total staff = 100
40% of female, i.e 40 female and 60 male
70% of female staff is married i.e. 70% of 40 female = 28
Number of unmarried female = 40 - 28 = 12
50% of male staff is married i.e 50% of 60 male = 30
Number of unmarried male = 60 - 30 = 30
Total number of unmarried staff = 12 + 30 = 42
% of unmarried staff = $$\frac{42}{100}$$ × 100   = 42%