Percentage - Aptitude MCQ Questions and Solutions with Explanations

Answer: Option E

= 140% of 56 + 56% of 140
$$\eqalign{ & = \left( {\frac{{140}}{{100}} \times 56} \right) + \left( {\frac{{56}}{{100}} \times 140} \right) \cr & = 78.4 + 78.4 \cr & = 156.8 \cr} $$

Answer: Option B

Number of rolls sold by noon = $$\frac{1}{2}$$ of 40 dozen = 20 dozen
Number of rolls sold between noon and closing time :
= 60% of 20 dozen
= $$\left( {\frac{{60}}{{100}} \times 20} \right)$$   dozen
= 12 dozen
Number of rolls left unsold :
= [40 - (20 + 12)] dozen
= 8 dozen

Answer: Option A

Let 35568 ÷ x% of 650 = 456
Then,
$$\eqalign{ & \Rightarrow 35568 \div \left( {\frac{x}{{100}} \times 650} \right) = 456 \cr & \Rightarrow \frac{{13x}}{2} \times 456 = 35568 \cr & \Rightarrow 2964x = 35568 \cr & \Rightarrow x = \frac{{35568}}{{2964}} \cr & \Rightarrow x = 12 \cr} $$

Answer: Option E

$$\eqalign{ & \frac{5}{6} = \left( {\frac{5}{6} \times 100} \right)\% \cr & \,\,\,\,\,\, = 83\frac{1}{3}\% \cr & \frac{2}{3} = \left( {\frac{2}{3} \times 100} \right)\% \cr & \,\,\,\,\,\, = 66\frac{2}{3}\% \cr & \frac{2}{5} = \left( {\frac{2}{5} \times 100} \right)\% \cr & \,\,\,\,\,\, = 40\% \cr & \frac{1}{4} = \left( {\frac{1}{4} \times 100} \right)\% \cr & \,\,\,\,\,\, = 25\% \cr & \frac{2}{{11}} = \left( {\frac{2}{{11}} \times 100} \right)\% \cr & \,\,\,\,\,\,\,\,\, = 18\frac{2}{{11}}\% < 20\% \cr} $$

Answer: Option C

Sonal's annual salary = Rs. 108000
∴ Sonal's monthly salary
= Rs. $$\left( {\frac{{108000}}{{12}}} \right)$$
= Rs. 9000
Nandini's monthely salary
= Rs. (9000 × 2)
= Rs. 18000
Let Kaushal's monthly salary be Rs. x
Then,
12% of x = 16% of 18000
⇒ $$\frac{{12}}{{100}}$$x = $$\left( {\frac{{16}}{{100}} \times 18000} \right)$$
⇒ $$\frac{{12}}{{100}}$$x = 2880
⇒ x = $$\left( {\frac{{2880 × 100}}{{12}}} \right)$$
⇒ x = 24000