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1
Sanjay made a profit of 8% by selling a shirt after offering a discount of 12%. If the marked price of the shirt is Rs. 1080, find cost price = ?
Discuss
Answer & Solution
Answer: Option C
Solution:
$$\eqalign{ & {\text{Marked price of shirt}} \cr & = {\text{Rs}}{\text{.1080}} \cr & {\text{Selling price of shirt}} \cr & = {\text{Rs}}{\text{.1080}} - \frac{{1080 \times 12}}{{100}} \cr & = {\text{Rs}}{\text{.}}\left( {1080 - 129.60} \right) \cr & = {\text{Rs}}.950.40 \cr & {\text{Let CP of shirt is Rs}}{\text{. }}x \cr & \therefore x + \frac{{x \times 8}}{{100}} = 950.40 \cr & \Rightarrow \frac{{108x}}{{100}} = 950.40 \cr & \Rightarrow x = 950.40 \times \frac{{100}}{{108}} \cr & \Rightarrow x = {\text{Rs}}{\text{. }}880 \cr} $$
2
A book seller allowed 10% discount on printed price. He gets 30% commission from publisher. His profit in percent will be?
Discuss
Answer & Solution
Answer: Option B
Solution:
Let the marked price be of book be Rs. 100
Cost price of the retailer = Rs. (100 - 30) = Rs. 70
Selling price for the retailer = Rs. 90
∴ Profit percent
$$\eqalign{ & = \left( {\frac{{90 - 70}}{{70}}} \right) \times 100 \cr & = \left( {\frac{{20}}{{70}}} \right) \times 100 \cr & = \frac{{200}}{7} \cr & = 28\frac{4}{7}\% \cr} $$
3
A shopkeeper increases the price of an object by 40% and then sells it at 25% discount on the marked price. If the selling price of such an object be Rs. 2100, its cost price for the shopkeeper was?
Discuss
Answer & Solution
Answer: Option D
Solution:
Let cost price of the article is 100
So, marked price = 140% of 100
$$ = \frac{{140}}{{100}} \times 100 = 140$$
Now, give 25% discount
So, Selling price
$$\eqalign{ & = 140 - 25\% {\text{ of 140}} \cr & = 140 - \frac{1}{4} \times 140 = 105 \cr & 105 \to 2100 \cr & 1 \to 20 \cr & 100 \to 20 \times 100 \cr & \,\,\,\,\,\,\,\,\,\,\, = {\text{Rs}}{\text{. }}2000 \cr} $$
4
By what fraction selling price must be multiplied to get the cost price, if the loss is 20% = ?
Discuss
Answer & Solution
Answer: Option C
Solution:
$$\eqalign{ & \% {\text{ Loss }} = 20\% \cr & 20\% = \frac{1}{5} \cr} $$
It Cost price = 5 units
Loss = 1 units
Selling price = 5 - 1 = 4 units
Selling price = 4
we make it equal to Cost price that is (5)
So, we multiply Selling price by
$$\eqalign{ & = \frac{5}{4} \cr & {\text{Selling price}} = 4 \times \frac{5}{4} \cr & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = 5{\text{ }} \cr} $$
5
The sale price of an article including the sales tax is Rs. 1232. The rate of sales tax is 10%. If the shopkeeper has made a profit of 12%, then the cost price of the article is = ?
Discuss
Answer & Solution
Answer: Option C
Solution:
Let the cost price of article be Rs. x
Profit = 12%
Rate of sales tax = 10%
Sale price of an article including sales tax = Rs. 1232
According to the question,
$$\eqalign{ & \Rightarrow \frac{{112x}}{{100}} + \frac{{112x \times 10}}{{10000}} = 1232 \cr & \Rightarrow \frac{{1120x + 112x}}{{1000}} = 1232 \cr & \Rightarrow 1232x = 1232 \times 1000 \cr & \Rightarrow x = {\text{Rs}}{\text{. }}1000 \cr} $$
6
Meena Kumari goes to a shop and buys a saree, costing Rs. 5225, including sales tax of 12%. The shopkeeper gives her a discount, so that the price is decreased by an amount equivalent to sales tax. The price is decreased by ( nearest value) ?
Discuss
Answer & Solution
Answer: Option C
Solution:
Price of the saree including sales tax = Rs. 5225
Cost price without sales tax
$$\eqalign{ & = \frac{{5225}}{{112}} \times 100 \cr & = 4665 \cr & {\text{The price decreased}} \cr & = {\text{Rs}}{\text{.}}\left( {5225 - 4665} \right) \cr & = {\text{Rs}}{\text{. }}560 \cr} $$
7
Ramesh sold a book at a loss of 30%. If he has sold it for Rs. 140 more, he would have made a profit of 40%. The cost price of the book is = ?
Discuss
Answer & Solution
Answer: Option B
Solution:
$$\eqalign{ & {\text{Loss}} = 30\% \cr & {\text{Let}}\,{\text{CP}} = x \cr & {\text{Loss}}\% = \frac{{{\text{CP}} - {\text{SP}}}}{{{\text{CP}}}} \times 100 \cr & \Rightarrow \frac{{30}}{{100}} = \frac{{x - {\text{SP}}}}{x} \cr & \Rightarrow 3x = 10x - 10{\text{SP}} \cr & \Rightarrow 7x = 10{\text{SP}} \cr & \Rightarrow {\text{SP}} = \frac{7}{{10}}x \cr & {\text{If}}\,{\text{SP}} = 140\,{\text{more}}\, = \frac{7}{{10}}x + 140 \cr & {\text{the}}\,{\text{profit}} = 40\% \cr & \Rightarrow \frac{{40}}{{100}} = \frac{{\frac{7}{{10}}x + 140 - x}}{x} \cr & \Rightarrow \frac{2}{5} = \frac{{1400 - 3x}}{{10x}} \cr & \Rightarrow 4x = 1400 - 3x \cr & \Rightarrow 7x = 1400 \cr & \Rightarrow x = 200 \cr & {\text{So,}}\,{\text{CP}} = {\text{Rs}}{\text{.}}\,200 \cr} $$
8
A sells a watch to B and makes a loss of 12%. B makes a profit of $$12\frac{1}{2}$$% by selling the watch to C. If A sells the watch to be at the cost of which C purchased it, then the percentage of loss or profit of A will be = ?
Discuss
Answer & Solution
Answer: Option A
Solution:
Let the CPA of Watch = 100
∴ SPA to B = 100 - 12% of 100 = 100 - 12 = 88
AND SPB to C = 88 + $$12\frac{1}{2}$$% of 88 = 88 + 11 = 99
If A sold the direct to C at price of B sold to C.
A got loss = 100 - 99 = 1
% loss $$= \frac{1}{{100}} \times 100 = 1\% $$
9
Supriya sold a washing machine for Rs. 8500. She incurred a loss of 15% in this transaction. At what price had she bought the washing machine ?
Discuss
Answer & Solution
Answer: Option A
Solution:
Selling price of washing machine = Rs. 8500
Loss % = 15%
Cost price of washing machine
$$\eqalign{ & = {\text{Rs}}{\text{.}}\left( {\frac{{100}}{{85}} \times 8500} \right) \cr & = {\text{Rs}}{\text{.10000}} \cr} $$
10
The price of an article is first increased by 20% and later on decreased by 25% due to reduction in sales. Find the net percentage change in final price of the article?
Discuss
Answer & Solution
Answer: Option D
Solution:
Let the price of article is Rs. 100
First increase % = 20%
After increase, price of article
$$\eqalign{ & = 100 \times \frac{{120}}{{100}} \cr & = {\text{Rs}}{\text{.120 }} \cr} $$
Second decrease % = 25%
After decrease, price of article
$$\eqalign{ & = 120 - \frac{{120 \times 25}}{{100}} \cr & = {\text{Rs}}{\text{. }}90 \cr} $$
Net change percent in price
$$\eqalign{ & = \frac{{100 - 90}}{{100}} \times 100 \cr & = \frac{{10}}{{100}} \times 100 \cr & = 10\% \cr} $$