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41
A train is 250 m long. If the train takes 50 second to cross a tree by the railway line, then the speed of the train on Km /hr is :
Discuss
Answer & Solution
Answer: Option C
Solution:
$$\eqalign{ & {\text{Speed}} = \frac{{{\text{Distance}}}}{{{\text{Time}}}} \cr & {\text{Speed}} = \frac{{250}}{{50}} = 5{\text{ m /s}} \cr & {\text{Speed}} = 5 \times \frac{{18}}{5} = 18{\text{ km /hr}} \cr} $$
42
Points 'A' and 'B' are 70 km apart on a highway and two cars start at the same time. If they travel in the same direction, they meet in 7 hours, but if they travel towards each other they meet in one hour. Find the speed of the two cars (in km/hr).
Discuss
Answer & Solution
Answer: Option B
Solution:
Let the speed of the cars be S1 and S2
And S1 - S2 = $$\frac{70}{7}$$ = 10 . . . . . (i)
Also S1 + S2 = $$\frac{70}{1}$$ = 70 . . . . . (ii)
From equation (i) and (ii)
S1 = $$\frac{10 + 70}{2}$$  = 40 km /hr
And S2 = $$\frac{70 - 10}{2}$$  = 30 km / hr
∴ Required speeds are 40 km/hr and 30 km/hr
43
A 75 metres long train is moving at 20 kmph. It will cross a man standing on the platform in :
Discuss
Answer & Solution
Answer: Option C
Solution:
T = $$\frac{D}{S}$$
   = $$\frac{75 × 18}{20 × 5}$$
   = $$\frac{27}{2}$$
   = 13.5 seconds
44
A car travels at a speed of 60 km/hr and covers a particular distance in one hour. How long will it take for another car to cover the same distance at 40 km/hr ?
Discuss
Answer & Solution
Answer: Option C
Solution:
Total distance = 60 km/hr × 1 hour = 60 km
Therefore,
Time will be taken by another car to travel the same distance with 40 km/hr
= $$\frac{60}{40}$$
= $$\frac{3}{2}$$ hours
45
A man walking at the rate of 5 km/hr crosses a bridge in 15 min. The length of the bridge (in metres) is :
Discuss
Answer & Solution
Answer: Option D
Solution:
$$\eqalign{ & 15\min = \frac{1}{4}{\text{hrs}} \cr & {\text{1 hr }} \to {\text{5 kms}} \cr & \frac{1}{4}{\text{hr}} \to \frac{5}{4}{\text{ kms}} \cr & {\text{So, length of the bridge}} \cr & = \frac{5}{4}{\text{ km}} \cr & {\text{ = 1250 metres}} \cr} $$
46
A gun is fired at a distance of 1.7 km from Ram and he hears the sound after 25 seconds. The speed of sound in meter per second is
Discuss
Answer & Solution
Answer: Option D
Solution:
$$\eqalign{ & {\text{Distance = 1}}{\text{.7 km}} \cr & {\text{Time = 25 sec}} \cr & \therefore {\text{Speed = }}\frac{{{\text{Distance}}}}{{{\text{Time }}}} \cr & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = \frac{{1.7 \times 1000}}{{25}} \cr & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = 68{\text{ m/s}} \cr} $$
47
A man crosses a road 250 metres wide in 75 seconds. His speed in km/hr is :
Discuss
Answer & Solution
Answer: Option B
Solution:
$$\eqalign{ & S = \frac{D}{T} = \frac{{250}}{{75}}{\text{ m/sec}} \cr & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{\text{ = }}\frac{{250}}{{75}} \times \frac{{18}}{5} \cr & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = 12{\text{ km/hr}} \cr} $$
48
The speed of 90 km per hour is same as :
Discuss
Answer & Solution
Answer: Option C
Solution:
1 km/hr = $$\frac{5}{18}$$
∴ 90 km/hr
= 90 × $$\frac{5}{18}$$ = 25 m/s
49
A train passes two bridges of length 500 metres and 250 metres in 100 seconds and 60 seconds respectively. The length of the train is :
Discuss
Answer & Solution
Answer: Option A
Solution:
Let the length of train be $$l$$ metre
According to the question,
Time = $$\frac{{{\text{Distance}}}}{{{\text{Speed}}}}$$
⇒ 100 =$$\frac{{{\text{500 + }}l}}{{{\text{Speed}}}}$$
⇒ Speed = $$\frac{{500 + l}}{{100}}$$    ..... (i)
Again,
60 = $$\frac{{{\text{250 + }}l}}{{{\text{Speed of Train}}}}$$
Speed = $$\frac{{{\text{250 + }}l}}{{{\text{60}}}}$$    ..... (ii)
Equation (i) and (ii)
$$\eqalign{ & \Rightarrow \frac{{500 + l}}{{100}} = \frac{{250}}{{60}} \cr & \Rightarrow 1500 + 3l = 1250 + 5l \cr & \Rightarrow 2l = 250 \cr & \therefore {\text{Length of train = 125 metres}} \cr} $$
50
Two trains start from a certain place on two parallel tracks in the same direction. The speed of the trains are 45 km/hr and 40 km/hr respectively. The distance between the two trains after 45 minutes will be :
Discuss
Answer & Solution
Answer: Option C
Solution:
Relative speed :
$$\eqalign{ & = \left( {40 - 45} \right) \times \frac{5}{{18}} \cr & = \frac{{25}}{{18}}{\text{ m/s}} \cr} $$
∴ Required distance :
$$\eqalign{ & {\text{ = }}\frac{{25}}{{18}} \times 45 \times 60 \cr & = 3750{\text{ metres or 3}}{\text{.75 km}} \cr} $$