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Speed Time And Distance - Aptitude MCQ Questions and Solutions with Explanations

Speed Time And Distance MCQ Questions and answers with easy and logical explanations.Arithmetic Ability provides you all type of quantitative and competitive aptitude mcq questions on Speed Time And Distance with easy and logical explanations. Speed Time And Distance MCQ is important for exams like Banking exams,IBPS,SCC,CAT,XAT,MAT etc. Page-9 section-4

Each section contains 100 MCQs on Speed Time and Distance .
81
Prasad goes 96 kilometres on a bike at a speed of 16 km/h, 124 kilometres at 31 km/h in a car, and 105 kilometres at 7 km/h in a horse cart. Find his average speed for the entire distance travelled.
Discuss
Answer & Solution
Answer: Option B
Solution:
$$\eqalign{ & {\text{Average speed}} = \frac{{96 + 124 + 105}}{{\frac{{96}}{{16}} + \frac{{124}}{{31}} + \frac{{105}}{7}}} \cr & = \frac{{325}}{{6 + 4 + 15}} \cr & = \frac{{325}}{{25}} \cr & = 13{\text{ kmph}} \cr} $$
82
Ram starts from point A at 8 a.m. and reaches point B at 2 p.m. on the same day. On the same day, Raju starts from point B at 8 a.m. and reaches point A at 6 p.m. on the same day. Both points A and B are separated by only a straight line track. At what time they both meet?
Discuss
Answer & Solution
Answer: Option A
Solution:
$$\overline {{\text{A}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{\text{B}}} $$
Ram takes = 6 hour
Raju takes = 10 hour
Let distance = 30 km
(LCM of 6, 10)
Speed of Ram = $$\frac{{30}}{6}$$ = 5 km/hr
Speed of Raju = $$\frac{{30}}{{10}}$$ = 3 km/hr
They will met at $$ = \frac{{30}}{8} = 3\frac{6}{8}$$
$$\eqalign{ & = 3\frac{3}{4} \times 60 = 3:45\,{\text{am}} \cr & {\text{Time}} = 8 + 3:45 = 11:45{\text{ am}} \cr} $$
83
A and B start moving towords each other from places X and Y, respectively, at the same time on the day. The speed of A is 20% more than of B. After meeting on the way, A and B take p hours and $$7\frac{1}{5}$$ hours, respectively. What is the value of p?
Discuss
Answer & Solution
Answer: Option B
Solution:
\[\begin{array}{*{20}{c}} {}&{\text{A}}&{}&{\text{B}} \\ {{\text{S}} \to }&6&:&5 \end{array}\]
$$\eqalign{ & \frac{{V1}}{{V2}} = \sqrt {\frac{{T2}}{{T1}}} \cr & \frac{6}{5} = \sqrt {\frac{{\frac{{36}}{5}}}{p}} \cr & \frac{{36}}{{25}} = \frac{{36}}{{5p}} \cr & p = 5 \cr} $$
84
Length of a train is 330 metres and it is moving at the speed of 72 km/hr. In how much time will it takes cross a platform of length 710 metres?
Discuss
Answer & Solution
Answer: Option D
Solution:
$$\eqalign{ & {\text{Time}} = \frac{{330 + 710}}{{72 \times \frac{5}{{18}}}}{\text{ Sec}}{\text{.}} \cr & = \frac{{1040}}{{20}}{\text{ Sec}}{\text{.}} \cr & = 52{\text{ Sec}}{\text{.}} \cr} $$
85
A train, 150 m long, is running at 90 km/h. How long (in seconds) will it take to clear a platform that is 300 m long?
Discuss
Answer & Solution
Answer: Option B
Solution:
$$\eqalign{ & 90{\text{ km/h}} \to \frac{{90 \times 5}}{{18}} = 25{\text{ m/s}} \cr & {\text{Time}} = \frac{{150 + 300}}{{25}} = 18\,{\text{seconds}} \cr} $$
86
A takes 2 hours more than B to cover a distance of 40 km. If A doubles his speed, he takes $$1\frac{1}{2}$$ hours more than B to cover 80 km. To cover a distance of 90 km, how much time will B take travelling at his same speed?
Discuss
Answer & Solution
Answer: Option B
Solution:
Speed Time and Distance mcq question image
Distance same
Speed = 1 : 2
Time = 2 : 1
1 unit → 2.5
2 unit → 2 × 2.5 = 5 hr
A = 5 hr
B = 1 hr
Speed of B = $$ = \frac{{80}}{1}$$ = 80 km/hr
Time $$ = \frac{{90}}{{80}} = 1\frac{1}{8}{\text{hr}}$$
87
Places A and B are 396 km apart. Train X leaves from A for B and train Y leaves from B for A at the same time on the same day on parallel tracks. Both trains meet after $$5\frac{1}{2}$$ hours. The speed of Y is 10 km/h more than that of X. What is the speed (in km/h) of Y?
Discuss
Answer & Solution
Answer: Option A
Solution:
\[A\xrightarrow{{\,\,\,\,\,\,\,\,\,\,396\,\,\,\,\,\,\,\,\,\,}}B\]
$$\eqalign{ & \frac{{396}}{{A + B}} = \frac{{11}}{2} \cr & X + Y = \frac{{396 \times 2}}{{11}} \cr & X + Y = 36 \times 2 \cr & X + Y = 72 \cr & {\text{Let,}} \cr & X = a \cr & Y = a + 10 \cr & a + a + 10 = 72 \cr & 2a = 62 \cr & a = 31{\text{ km/h}} \cr & Y = 31 + 10 = 41 \cr} $$
88
A train travels the distance between stations P and Q at a speed of 126 km/h, while in the opposite direction it comes back at 90 km/h. Another train travels the same distance at the average speed of the first train. The time taken by the second train to travel 525 km is:
Discuss
Answer & Solution
Answer: Option A
Solution:
$$\eqalign{ & {\text{Average speed}} = \frac{{2 \times 90 \times 126}}{{216}} \cr & = \frac{{2 \times 5 \times 126}}{{12}} \cr & = 105{\text{ km/h}} \cr & {\text{Time}} = \frac{{525}}{{105}} = 5{\text{ hours}} \cr} $$
89
Shyam drives his car 30 km at a speed of 45 km/h and, for the next 1 h 20 m, he drives it at a speed of 51 km/h. Find his average speed (in km/h) for the entire journey.
Discuss
Answer & Solution
Answer: Option A
Solution:
$$\eqalign{ & {\text{Time}} = 1\,{\text{hr}}\,20\,{\text{m}} = \frac{4}{3}{\text{hr}} \cr & {\text{Speed}} = 51{\text{ km/hr}} \cr & \therefore {\text{Distance}} = \frac{4}{3} \times 51 = 68 \cr & {\text{Average speed}} = \frac{{{\text{Total distance}}}}{{{\text{Total time}}}} \cr & = \frac{{30 + 68}}{{\frac{{30}}{{45}} + \frac{4}{3}}} \cr & = \frac{{98}}{{\frac{2}{3} + \frac{4}{3}}} \cr & = 49{\text{ km/hr}} \cr} $$
90
Renu was sitting inside train A, which was travelling at 50 km/h. Another train, B whose length was three times the length of A crossed her in the opposite direction in 15 seconds. If the speed of train B was 58 km/h. Then the length of train A (in m) is:
Discuss
Answer & Solution
Answer: Option D
Solution:
$$\eqalign{ & {\text{Lenth of train A}} = l \cr & {\text{Lenth of train B}} = 3l \cr & \frac{{3l}}{{\left( {50 + 58} \right) \times \frac{5}{{18}}}} = 15 \cr & \frac{{3l \times 18}}{{108}} = 15 \times 5 \cr & l = 150{\text{ m}} \cr} $$