Arrange the following fraction in decreasing order : $$\frac{3}{5},$$ $$\frac{7}{9}$$ $$,\frac{{11}}{{13}}$$
A. $$\frac{3}{5},\frac{7}{9},\frac{{11}}{{13}}$$
B. $$\frac{7}{9},\frac{3}{5},\frac{{11}}{{13}}$$
C. $$\frac{{11}}{{13}},\frac{7}{9},\frac{3}{5}$$
D. $$\frac{{11}}{{13}},\frac{3}{5},\frac{7}{9}$$
Answer: Option C
Solution(By Examveda Team)
$$\frac{3}{5},\frac{7}{9},\frac{{11}}{{13}}$$$$\eqalign{ & \frac{3}{5} = 0.60, \cr & \frac{7}{9} = 0.7, \cr & \frac{{11}}{{13}} = 0.8 \cr & \frac{{11}}{{13}}{\text{ > }}\frac{7}{9} > \frac{3}{5} \cr} $$
Related Questions on Number System
Three numbers are in ratio 1 : 2 : 3 and HCF is 12. The numbers are:
A. 12, 24, 36
B. 11, 22, 33
C. 12, 24, 32
D. 5, 10, 15
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