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By how much does $$\frac{6}{{\frac{7}{8}}}$$ exceed $$\frac{{\frac{6}{7}}}{8}$$ ?
Answer & Solution
Correct Answer:
Option
B
$$\eqalign{
& \frac{6}{{\frac{7}{8}}} = \frac{{6 \times 8}}{7} = \frac{{48}}{7} \cr
& \frac{{\frac{6}{7}}}{8} = \frac{6}{{7 \times 8}} = \frac{6}{{56}} = \frac{3}{{28}} \cr
& {\text{Difference - }} \cr
& = \frac{{48}}{7} - \frac{3}{{28}} \cr
& = \frac{{192 - 3}}{{28}} \cr
& = \frac{{189}}{{28}} \cr
& = \frac{{27}}{4} \cr
& = 6\frac{3}{4} \cr} $$
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