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Calculate the pH of 0.01 M HCl solution
Answer & Solution
Correct Answer:
Option
A
HCl is a strong acid and it dissociates into ions completely.
HCl (aq) 0.01 M → H+ (0.01 M) + Cl− (0.01 M)
[H+ (aq)] = 0.01 M = 1 × 10-2
pH = - log10 [H+ (aq)]
pH= - log10 [1 × 10-2]
therefore pH = 2
HCl (aq) 0.01 M → H+ (0.01 M) + Cl− (0.01 M)
[H+ (aq)] = 0.01 M = 1 × 10-2
pH = - log10 [H+ (aq)]
pH= - log10 [1 × 10-2]
therefore pH = 2
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