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Stoichiometry MCQ Questions & Answers | Chemical Engineering

Learn Stoichiometry MCQ questions & answers are available for a Chemical Engineering students to clear GATE exams, various technical interview, competitive examination, and another entrance exam. Stoichiometry MCQ question is the important chapter for a Chemical Engineering and GATE students. Page-7 section-1

Each section contains 100 MCQs on Stoichiometry .
61
If the pH value of a solution changes by one unit, it implies that hydrogen ion concentration in the solution will change __________ times.
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Answer & Solution
Answer: Option A
No explanation is given for this question. Let's Discuss on Board
62
The atomic heat capacities of all solid elements __________ with decrease in temperature.
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Answer & Solution
Answer: Option B
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63
At higher temperature, molal heat capacities of most of the gases (at constant pressure) __________ with increase in temperature.
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Answer: Option A
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64
At higher temperatures, molal heat capacities for most of the gases (at constant pressure) __________ with increase in temperature.
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Answer: Option B
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65
Assuming that CO2 obeys perfect gas law, calculate the density of CO2 (in kg/m3) at 263°C and 2 atm.
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Answer: Option B
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66
1 Pascal (unit of pressure) is equal to __________ N/m2.
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Answer: Option B
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67
The unit of specific heat at constant pressure, Cp, in SI unit is
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Answer: Option B
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68
Cp - Cv, for an ideal gas is equal to
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Answer: Option A
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69
With increase in temperature, the surface tension of water
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Answer: Option B
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70
The temperature of a gas in a closed container is 27° C. If the temperature of the gas is incresed to 300° C, then the pressure exerted is
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Answer & Solution
Answer: Option A
Solution:
According to Gay-Lussac's Law, for a gas at constant volume, the pressure is directly proportional to the absolute temperature: P ∝ T.

First, convert the given temperatures to Kelvin:

Initial temperature (T₁): 27°C + 273 = 300 K

Final temperature (T₂): 300°C + 273 = 573 K

Using the formula P₂ = P₁ × (T₂ / T₁):

P₂ = P₁ × (573 / 300) ≈ P₁ × 1.91

This shows that the final pressure is approximately 1.91 times the initial pressure, which is nearly double.

Therefore, the pressure exerted is best described as doubled.