Choose the correct option to fill? X so that the code given below implements the Heap sort.
#include <stdio.h>
void heapify(int arr[], int n, int i)
{
int largest = i; // Initialize largest as root
int l = 2*i + 1; // left = 2*i + 1
int r = 2*i + 2; // right = 2*i + 2
if (l < n && arr[l] > arr[largest])
largest = l;
if (r < n && arr[r] > arr[largest])
largest = r;
if (largest != i)
{
swap(arr[i], arr[largest]);
heapify(arr, n, largest);
}
}
void heapSort(int arr[], int n)
{
for (int i = n / 2 - 1; i >= 0; i--)
heapify(arr, n, i);
for (int i=n-1; i>=0; i--)
{
X;
heapify(arr, i, 0);
}
}
void printArray(int arr[], int n)
{
for (int i=0; i<n; ++i)
printf(“%d”,arr[i]);
printf(“\n”);
}
int main()
{
int arr[] = {12, 11, 13, 5, 6, 7};
int n = sizeof(arr)/sizeof(arr[0]);
heapSort(arr, n);
printf(“Sorted array is \n");
printArray(arr, n);
}
#include <stdio.h>
void heapify(int arr[], int n, int i)
{
int largest = i; // Initialize largest as root
int l = 2*i + 1; // left = 2*i + 1
int r = 2*i + 2; // right = 2*i + 2
if (l < n && arr[l] > arr[largest])
largest = l;
if (r < n && arr[r] > arr[largest])
largest = r;
if (largest != i)
{
swap(arr[i], arr[largest]);
heapify(arr, n, largest);
}
}
void heapSort(int arr[], int n)
{
for (int i = n / 2 - 1; i >= 0; i--)
heapify(arr, n, i);
for (int i=n-1; i>=0; i--)
{
X;
heapify(arr, i, 0);
}
}
void printArray(int arr[], int n)
{
for (int i=0; i<n; ++i)
printf(“%d”,arr[i]);
printf(“\n”);
}
int main()
{
int arr[] = {12, 11, 13, 5, 6, 7};
int n = sizeof(arr)/sizeof(arr[0]);
heapSort(arr, n);
printf(“Sorted array is \n");
printArray(arr, n);
}A. swap(arr[0], arr[n])
B. swap(arr[i], arr[n])
C. swap(arr[0], arr[i])
D. swap(arr[i], arr[2*i])
Answer: Option C

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