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91
Height of instrument method of levelling is
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Answer: Option C
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92
The slotted template method
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Answer: Option D
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93
When a star is between the pole and the horizon, the relationship between latitude (λ), zenith distance (z) and declination δ, is
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Answer: Option C
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94
The length of a parallel of λ latitude between two meridians is equal to difference in longitudes multiplied by
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Answer: Option B
Solution:
In surveying, the length of a parallel of latitude (λ) between two meridians is equal to the difference in longitudes multiplied by the cosine of the latitude (λ). This relationship arises from the spherical geometry of the Earth's surface. As you move away from the equator towards the poles, the parallels of latitude become shorter due to the convergence of meridians towards the poles. The cosine of the latitude accounts for this reduction in length as you move away from the equator. Therefore, the correct option is Option B: cos λ.
95
The hour angle of the heavenly body for Greenwich meridian equals the hour angle of the body for any other meridian + longitude:
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Answer: Option D
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96
Which of the following is not used in measuring perpendicular offsets ?
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Answer: Option A
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97
The nearest star is so far away from the earth that the directions to it from two diametrically opposite points on the earth differs less than
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Answer: Option C
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98
Right ascension of a heavenly body is its equatorial angular distance measured
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Answer: Option B
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99
$$\alpha $$ and $$\beta $$ are the angles subtended by a point of elevation h at their air station with respective plumb points. Photo scale and focal length of the lens being ‘S’ and ‘f’ respectively. Parallax displacement of the point due to relief, is
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Answer: Option C
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100
The method of surveying by triangulation was first introduced by the Dutchman Snell in
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Answer: Option B
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