Consider the differential equation: $$\frac{{{\text{dy}}}}{{{\text{dx}}}} = \left( {1 + {{\text{y}}^2}} \right){\text{x}}{\text{.}}$$
The general solution with constant c is
A. $${\text{y}} = \tan \frac{{\text{x}}}{2} + \tan {\text{c}}$$
B. $${\text{y}} = {\tan ^2}\left( {\frac{{\text{x}}}{2} + {\text{c}}} \right)$$
C. $${\text{y}} = {\tan ^2}\left( {\frac{{\text{x}}}{2}} \right) + {\text{c}}$$
D. $${\text{y}} = \tan \left( {\frac{{{{\text{x}}^2}}}{2} + {\text{c}}} \right)$$
Answer: Option D

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