Consider the following code:
#include<stdio.h>
int get_min(int a, int b)
{
if(a<b)
return a;
return b;
}
int minimum_time_required(int reach[][3],int spent[][4], int *entry, int *exit, int n)
{
int t1[n], t2[n],i;
t1[0] = entry[0] + spent[0][0];
t2[0] = entry[1] + spent[1][0];
for(i = 1; i < n; i++)
{
t1[i] = get_min(t1[i-1]+spent[0][i], t2[i-1]+reach[1][i-1]+spent[0][i]);
__________;
}
return get_min(t1[n-1]+exit[0], t2[n-1]+exit[1]);
}
Which of the following lines should be inserted to complete the above code?
#include<stdio.h>
int get_min(int a, int b)
{
if(a<b)
return a;
return b;
}
int minimum_time_required(int reach[][3],int spent[][4], int *entry, int *exit, int n)
{
int t1[n], t2[n],i;
t1[0] = entry[0] + spent[0][0];
t2[0] = entry[1] + spent[1][0];
for(i = 1; i < n; i++)
{
t1[i] = get_min(t1[i-1]+spent[0][i], t2[i-1]+reach[1][i-1]+spent[0][i]);
__________;
}
return get_min(t1[n-1]+exit[0], t2[n-1]+exit[1]);
}A. t2[i] = get_min(t2[i-1]+spent[1][i], t1[i-1]+reach[0][i-1]+spent[1][i])
B. t2[i] = get_min(t2[i-1]+spent[1][i], t1[i-1]+spent[1][i])
C. t2[i] = get_min(t2[i-1]+spent[1][i], t1[i-1]+reach[0][i-1])
D. none of the mentioned
Answer: Option A

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