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Data Interpretation MCQ Questions and Answers - Bar Chart

Learn Bar Chart Data Interpretation mcq question and answers with easy and logical explanations Page-10 section-1

Direction (1 - 5): Study the following bar graph and the table carefully and answer the questions given below:
Time Taken (in hours) by 6 Vehicles on Two Different Days
Direction image of Bar Chart chapter
Distance Covered (in km) by 6 Vehicles on Each Day
Vehicles Day 1 Day 2
A 832 864
B 516 774
C 693 810
D 552 765
E 935 546
F 703 636
1
Which of the following vehicles travelled at the same speed on both the days?
Discuss
Answer & Solution
$$\eqalign{ & \text{Speeds of vehicles on Day 1:} \cr & \text{A → } \frac{832}{16}\text{ km/hr}=\text{52 km/hr} \cr & \text{B → } \frac{516}{12}\text{ km/hr}=\text{43 km/hr} \cr & \text{C → } \frac{693}{11}\text{ km/hr}=\text{63 km/hr} \cr & \text{D → } \frac{552}{12}\text{ km/hr}=\text{46 km/hr} \cr & \text{E → } \frac{935}{17}\text{ km/hr}=\text{55 km/hr} \cr & \text{F → } \frac{703}{19}\text{ km/hr}=\text{37 km/hr} \cr & \cr & \text{Speed of vehicles on Day 2:} \cr & \text{A → } \frac{864}{16}\text{ km/hr}=\text{54 km/hr} \cr & \text{B → } \frac{774}{18}\text{ km/hr}=\text{43 km/hr} \cr & \text{C → } \frac{810}{18}\text{ km/hr}=\text{45 km/hr} \cr & \text{D → } \frac{765}{15}\text{ km/hr}=\text{51 km/hr} \cr & \text{E → } \frac{546}{14}\text{ km/hr}=\text{39 km/hr} \cr & \text{F → } \frac{636}{12}\text{ km/hr}=\text{53 km/hr} \cr} $$

Clearly B travelled at the same speed on both the days.
2
What was the speed of vehicles C on Day 2 in terms of metres per second ?
Discuss
Answer & Solution
$$\eqalign{ & \text{Speeds of vehicles on Day 1:} \cr & \text{A → } \frac{832}{16}\text{ km/hr}=\text{52 km/hr} \cr & \text{B → } \frac{516}{12}\text{ km/hr}=\text{43 km/hr} \cr & \text{C → } \frac{693}{11}\text{ km/hr}=\text{63 km/hr} \cr & \text{D → } \frac{552}{12}\text{ km/hr}=\text{46 km/hr} \cr & \text{E → } \frac{935}{17}\text{ km/hr}=\text{55 km/hr} \cr & \text{F → } \frac{703}{19}\text{ km/hr}=\text{37 km/hr} \cr & \cr & \text{Speed of vehicles on Day 2:} \cr & \text{A → } \frac{864}{16}\text{ km/hr}=\text{54 km/hr} \cr & \text{B → } \frac{774}{18}\text{ km/hr}=\text{43 km/hr} \cr & \text{C → } \frac{810}{18}\text{ km/hr}=\text{45 km/hr} \cr & \text{D → } \frac{765}{15}\text{ km/hr}=\text{51 km/hr} \cr & \text{E → } \frac{546}{14}\text{ km/hr}=\text{39 km/hr} \cr & \text{F → } \frac{636}{12}\text{ km/hr}=\text{53 km/hr} \cr} $$

$$\eqalign{ & \text{Speed of C on Day 2} \cr & = 45 \text{ km/hr} \cr & = \left(45\times\frac{5}{18}\right) \text{m/sec} \cr & = \frac{25}{2} \text{ m/s} \cr & = 12.5 \text{ m/s} \cr} $$
3
What is the ratio of the speeds of vehicle D and vehicle E on Day 2?
Discuss
Answer & Solution
$$\eqalign{ & \text{Speeds of vehicles on Day 1:} \cr & \text{A → } \frac{832}{16}\text{ km/hr}=\text{52 km/hr} \cr & \text{B → } \frac{516}{12}\text{ km/hr}=\text{43 km/hr} \cr & \text{C → } \frac{693}{11}\text{ km/hr}=\text{63 km/hr} \cr & \text{D → } \frac{552}{12}\text{ km/hr}=\text{46 km/hr} \cr & \text{E → } \frac{935}{17}\text{ km/hr}=\text{55 km/hr} \cr & \text{F → } \frac{703}{19}\text{ km/hr}=\text{37 km/hr} \cr & \cr & \text{Speed of vehicles on Day 2:} \cr & \text{A → } \frac{864}{16}\text{ km/hr}=\text{54 km/hr} \cr & \text{B → } \frac{774}{18}\text{ km/hr}=\text{43 km/hr} \cr & \text{C → } \frac{810}{18}\text{ km/hr}=\text{45 km/hr} \cr & \text{D → } \frac{765}{15}\text{ km/hr}=\text{51 km/hr} \cr & \text{E → } \frac{546}{14}\text{ km/hr}=\text{39 km/hr} \cr & \text{F → } \frac{636}{12}\text{ km/hr}=\text{53 km/hr} \cr} $$

$$\eqalign{ & \text{Required ratio} \cr & = \frac{\text{Speed of D on Day 2}}{\text{Speed of E on Day 2}} \cr & = \frac{51}{39} \cr & = \frac{17}{13} \cr & = 17 : 13 \cr} $$
4
What was the difference between the speed of vehicles A on Day 1 and the speed of vehicles C on the same day ?
Discuss
Answer & Solution
$$\eqalign{ & \text{Speeds of vehicles on Day 1:} \cr & \text{A → } \frac{832}{16}\text{ km/hr}=\text{52 km/hr} \cr & \text{B → } \frac{516}{12}\text{ km/hr}=\text{43 km/hr} \cr & \text{C → } \frac{693}{11}\text{ km/hr}=\text{63 km/hr} \cr & \text{D → } \frac{552}{12}\text{ km/hr}=\text{46 km/hr} \cr & \text{E → } \frac{935}{17}\text{ km/hr}=\text{55 km/hr} \cr & \text{F → } \frac{703}{19}\text{ km/hr}=\text{37 km/hr} \cr & \cr & \text{Speed of vehicles on Day 2:} \cr & \text{A → } \frac{864}{16}\text{ km/hr}=\text{54 km/hr} \cr & \text{B → } \frac{774}{18}\text{ km/hr}=\text{43 km/hr} \cr & \text{C → } \frac{810}{18}\text{ km/hr}=\text{45 km/hr} \cr & \text{D → } \frac{765}{15}\text{ km/hr}=\text{51 km/hr} \cr & \text{E → } \frac{546}{14}\text{ km/hr}=\text{39 km/hr} \cr & \text{F → } \frac{636}{12}\text{ km/hr}=\text{53 km/hr} \cr} $$

Difference between the speed of A on Day 1 and speed of C on Day 1
= (63 - 52) km/hr
= 11 km/hr
5
The distance travelled by vehicle F on Day 2 was approximately what percent of the distance travelled by it on Day 1?
Discuss
Answer & Solution
$$\eqalign{ & \text{Speeds of vehicles on Day 1:} \cr & \text{A → } \frac{832}{16}\text{ km/hr}=\text{52 km/hr} \cr & \text{B → } \frac{516}{12}\text{ km/hr}=\text{43 km/hr} \cr & \text{C → } \frac{693}{11}\text{ km/hr}=\text{63 km/hr} \cr & \text{D → } \frac{552}{12}\text{ km/hr}=\text{46 km/hr} \cr & \text{E → } \frac{935}{17}\text{ km/hr}=\text{55 km/hr} \cr & \text{F → } \frac{703}{19}\text{ km/hr}=\text{37 km/hr} \cr & \cr & \text{Speed of vehicles on Day 2:} \cr & \text{A → } \frac{864}{16}\text{ km/hr}=\text{54 km/hr} \cr & \text{B → } \frac{774}{18}\text{ km/hr}=\text{43 km/hr} \cr & \text{C → } \frac{810}{18}\text{ km/hr}=\text{45 km/hr} \cr & \text{D → } \frac{765}{15}\text{ km/hr}=\text{51 km/hr} \cr & \text{E → } \frac{546}{14}\text{ km/hr}=\text{39 km/hr} \cr & \text{F → } \frac{636}{12}\text{ km/hr}=\text{53 km/hr} \cr} $$

$$\eqalign{ & \text{Required %} \cr & = \left(\frac{636}{703}\times100\right)\% \cr & = \frac{63600}{703}\% \cr & = 90.46\% \cr & \approx 90\% \cr} $$